2[3x-2(x-3)-1]-(7-3x)=8

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Solution for 2[3x-2(x-3)-1]-(7-3x)=8 equation: 


Simplifying
2[3x + -2(x + -3) + -1] + -1(7 + -3x) = 8

Reorder the terms:
2[3x + -2(-3 + x) + -1] + -1(7 + -3x) = 8
2[3x + (-3 * -2 + x * -2) + -1] + -1(7 + -3x) = 8
2[3x + (6 + -2x) + -1] + -1(7 + -3x) = 8

Reorder the terms:
2[6 + -1 + 3x + -2x] + -1(7 + -3x) = 8

Combine like terms: 6 + -1 = 5
2[5 + 3x + -2x] + -1(7 + -3x) = 8

Combine like terms: 3x + -2x = 1x
2[5 + 1x] + -1(7 + -3x) = 8
[5 * 2 + 1x * 2] + -1(7 + -3x) = 8
[10 + 2x] + -1(7 + -3x) = 8
10 + 2x + (7 * -1 + -3x * -1) = 8
10 + 2x + (-7 + 3x) = 8

Reorder the terms:
10 + -7 + 2x + 3x = 8

Combine like terms: 10 + -7 = 3
3 + 2x + 3x = 8

Combine like terms: 2x + 3x = 5x
3 + 5x = 8

Solving
3 + 5x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5x = 8 + -3

Combine like terms: 3 + -3 = 0
0 + 5x = 8 + -3
5x = 8 + -3

Combine like terms: 8 + -3 = 5
5x = 5

Divide each side by '5'.
x = 1

Simplifying
x = 1

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